Step 3: To find the voltage across each
wire
RT = R1 + R2 + R3 + R4
RT = 20Ω + 1.5Ω + 4Ω + 15Ω
RT = 40.5 Ω
Across the 6Ω wire alone 푉 = 퐼푅1
1
푉 = 2 × 6
1
Step 4: To find the total current, I
푉 = 12푉
1
V
I =
R
Across the 4Ω wire alone 푉 = 퐼푅2
2
9 V
I =
푉 = 2 × 4
2
40.5 Ω
푉 = 8푉
2
I = 0.22 A
Therefore, the current reading on the
ammeter in the circuit is 0.22 A
Example 03
A circuit consists of a 1Ω wire in series with
a parallel arrangement of 6Ω and 3Ω and a
potential difference of 12V is connected
across the whole circuit. Calculate the
currents in each of the wires and the p.d
across each.
Example 02
A resistance of 6Ω is in series with one of
4Ω and a p.d of 20V is applied across the
whole arrangement. Calculate the current in
each wire and the p.d across each.
Solution
Consider the diagram below which shows
the conditions for the problem
Solution
20V is the p.d across both wires together
Step 1: To find the total resistance in
the circuit
Resistance in series = 푅1 + 푅2
Resistance in series = 6Ω + 4Ω
Resistance in series = 10Ω
Solution
Step 2: To find the total current in the
circuit
Since the 12V p.d is across the whole
circuit, then we must first find the total
resistance in the circuit.
푣표푙푡푎푔푒
푐푢푟푟푒푛푡 =
푟푒푠푖푠푡푎푛푐푒
Step1: To find the resistance of the
parallel circuit of 6Ω and the 3Ω resistors
20
푐푢푟푟푒푛푡 =
10
1
1
1
=
+
푐푢푟푟푒푛푡 = 2퐴
푅푝
푅1
푅2